Class 6 - Mathematics
Chapter - Perimeter and Area : Exercise 11.1
Top Block 1
Question : 1.The length and breadth of a rectangular piece of land are 500 m and 300 m respectively. Find:
(i) Its area.
(ii) The cost of the land, if 1 𝓂2of the land costs Rs. 10,000.
Answer :
Given: Length of a rectangular piece of land = 500 m and
Breadth of a rectangular piece of land = 300 m
(i) Area of a rectangular piece of land = Length x Breadth
= 500 x 300 = 1,50,000𝓂2
(ii) Since, the cost of 1 𝓂2land = Rs. 10,000
Therefore, the cost of 1,50,000 𝓂2 land = 10,000 x 1,50,000
= Rs. 1,50,00,00,000
Question : 2.Find the area of a square park whose perimeter is 320 m.
Answer :
Given: Perimeter of square park = 320 m
⇒ 4 x side = 320
⇒side = 320⁄4 = 80 m
Now, Area of square park = side x side
= 80 x 80 = 6400 𝓂2
Thus, the area of square park is 6400𝓂2.
Question : 3.Find the breadth of a rectangular plot of land, if its area is 440 𝓂2and the length is 22 m. Also find its perimeter.
Answer :
Area of rectangular park = 440 𝓂2
⇒length x breadth = 440 𝓂2
⇒ 22 x breadth = 440
⇒breadth = 440⁄22= 20 m
Now, Perimeter of rectangular park = 2 (length + breadth)
= 2 (22 + 20)
= 2 x 42 = 84 m
Thus, the perimeter of rectangular park is 84 m.
Question : 4.The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area.
Answer :
Perimeter of the rectangular sheet = 100 cm
⇒ 2 (length + breadth) = 100 cm
⇒ 2 (35 + breadth) = 100
⇒ 35 + breadth = 100⁄2
⇒ 35 + breadth = 50
⇒breadth = 50 – 35
⇒breadth = 15 cm
Now, Area of rectangular sheet = length x breadth
= 35 x 15 = 525c𝓂2
Thus, breadth and area of rectangular sheet are 15 cm and 525 c𝓂2respectively.
Question : 5.The area of a square park is the same as of a rectangular park. If the side of the square park is 60 m and the length of the rectangular park is 90 cm, find the breadth of the rectangular park.
Answer :
Given: The side of the square park = 60 m
The length of the rectangular park = 90 m
According to the Question,
Area of square park = Area of rectangular park
⇒side x side = length x breadth
⇒ 60 x 60 = 90 x breadth
⇒breadth = (60 × 60)⁄90 = 40 m
Thus, the breadth of the rectangular park is 40 m.
Question : 6. A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?
Answer :
According to the Question,
Perimeter of square = Perimeter of rectangle
⇒ 4 x side = 2 (length + breadth)
⇒ 4 x side = 2 (40 + 22) ⇒ 4 x side = 2 x 62
⇒side = (2×62)⁄4= 31 cm
Thus, the side of the square is 31 cm.
Now, Area of rectangle = length x breadth = 40 x 22 = 880 cm2
And Area of square = side x side = 31 x 31 = 961 cm2
Therefore, on comparing, the area of square is greater than that of rectangle.
Mddle block 1
Question : 7. The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is 30 cm, find its length. Also, find the area of the rectangle.
Answer :
Perimeter of rectangle = 130 cm
⇒ 2 (length + breadth) = 130 cm
⇒ 2 (length + 30) = 130
⇒length + 30 = 130⁄2
⇒length + 30 = 65
⇒length = 65 – 30 = 35 cm
Now area of rectangle = length x breadth = 35 x 30 = 1050 cm2
Thus, the area of rectangle is 1050 cm2.
Question : 8.A door of length 2 m and breadth 1 m is fitted in a wall. The length of the wall is 4.5 m and the breadth is 3.6 m. Find the cost of white washing the wall, if the rate of white washing the wall is Rs. 20 per𝓂2.
Answer :
Area of rectangular door = length x breadth = 2 m x 1 m = 2 𝓂2
Area of wall including door = length x breadth = 4.5 m x 3.6 m = 16.2 𝓂2
Now, Area of wall excluding door
= Area of wall including door – Area of door
= 16.2 – 2 = 14.2𝓂2
Since, The rate of white washing of 1 𝓂2the wall = Rs. 20
Therefore, the rate of white washing of 14.2𝓂2 the wall = 20 x 14.2
= Rs. 284
Thus, the cost of white washing the wall excluding the door is Rs. 284.
