Class 6 - Mathematics
Chapter - Practical Geometry : Exercise 10.5
Top Block 1
Question : 1.Construct the right angled ΔPQR, where 𝓂∠Q = 90o, QR = 8 cm and PR = 10 cm.
Answer :
To construct: A right angled triangle PQR where 𝓂∠Q = 90o, QR = 8 cm and PQ = 10 cm.
Steps of construction:
(a) Draw a line segment QR = 8 cm.
(b) At point Q, draw QX ⊥ QR.
(c) Taking R as centre, draw an arc of radius 10 cm.
(d) This arc cuts QX at point P.
(e) Join PQ.
It is the required right angled triangle PQR.
(a) Draw a line segment QR = 8 cm.
(b) At point Q, draw QX ⊥ QR.
(c) Taking R as centre, draw an arc of radius 10 cm.
(d) This arc cuts QX at point P.
(e) Join PQ.
It is the required right angled triangle PQR.
Question : 2.Construct a right angled triangle whose hypotenuse is 6 cm long and one the legs is 4 cm long.
Answer :
To construct: A right angled triangle DEF where DF = 6 cm and EF = 4 cm
Mddle block 1
Steps of construction:
(a) Draw a line segment EF = 4 cm.
(b) At point Q, draw EX ⊥ EF.
(c) Taking F as centre and radius 6 cm, draw an arc. (Hypotenuse)
(d) This arc cuts the EX at point D.
(e) Join DF.
It is the required right angled triangle DEF.
(a) Draw a line segment EF = 4 cm.
(b) At point Q, draw EX ⊥ EF.
(c) Taking F as centre and radius 6 cm, draw an arc. (Hypotenuse)
(d) This arc cuts the EX at point D.
(e) Join DF.
It is the required right angled triangle DEF.
Question : 3.Construct an isosceles right angled triangle ABC, where 𝓂∠ACB = 90o and AC = 6 cm.
Answer :
To construct: An isosceles right angled triangle ABC where 𝓂∠C = 90o, AC = BC = 6 cm.
Steps of construction:
(a) Draw a line segment AC = 6 cm.
(b) At point C, draw XC ⊥ CA.
(c) Taking C as centre and radius 6 cm, draw an arc.
(d) This arc cuts CX at point B.
(e) Join BA.
It is the required isosceles right angled triangle ABC.
(a) Draw a line segment AC = 6 cm.
(b) At point C, draw XC ⊥ CA.
(c) Taking C as centre and radius 6 cm, draw an arc.
(d) This arc cuts CX at point B.
(e) Join BA.
It is the required isosceles right angled triangle ABC.
