NCERT Solutions Class 7 Mathematics Simple Equations Ex 4.3

Class 6 - Mathematics
Chapter - Simple Equations : Exercise 4.3

NCERT Solutions Class 7 Mathematics textbook
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Question: 1.Solve the following equations:
(a) 2y + 52 = 372

(b) 5t + 28 = 10

(c) a5 + 3 = 2

(d) q4 + 7 = 5

(e) 52x = 10

(f) 52x = 254

(g) 7m + 192 = 13

(h) 6z + 10 = –2

(i) 3l2 = 23

(j) 2b3 – 5 = 3

Answer :

NCERT Solutions Class 7 Mathematics Simple Equations
NCERT Solutions Class 7 Mathematics Simple Equations

Question: 2.Solve the following equations:
(a) 2 (x + 4) = 12

(b) 3 (n – 5) = 21

(c) 3 (n – 5) = –21

(d) 3 – 2(2 – y) = 7

(e) –4 (2 – x) = 9

(f) 4(2 – x) = 9

(g) 4 +5 (p –1 ) = 34

(h) 34 –5(p – 1) = 4

Answer :

NCERT Solutions Class 7 Mathematics Simple Equations
NCERT Solutions Class 7 Mathematics Simple Equations
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Question: 3.Solve the following equations:
(a) 4 = 5 (p – 2)

(b) –4 = 5 (p – 2)

(c) –16 = –5(2 – p)

(d) 10 = 4 + 3 (t + 2)

(e) 28 = 4 + 3(t + 5)

(f) 0 = 16 + 4(m – 6)

Answer :

NCERT Solutions Class 7 Mathematics Simple Equations
NCERT Solutions Class 7 Mathematics Simple Equations

Question: 4.
(a) Construct 3 equations starting with x = 2.

(b) Construct 3 equations starting with x = –2.

Answer :
(a) 3 equations starting with x = 2.

(i) x = 2

Multiplying both sides by 10, 10x = 20

Adding 2 both sides 10x + 2 = 20 + 2 = 10x + 2 = 22

(ii) x = 2

Multiplying both sides by 5 5x = 10

Subtracting 3 from both sides 5x – 3 = 10 –3 = 5x – 3 = 7

(iii) x = 2

Dividing both sides by 5 x5 = 25

(b) 3 equations starting with x = –2.

(i) x = –2

Multiplying both sides by 3 3x = –6

(ii) x = –2

Multiplying both sides by 3 3x = –6

Adding 7 to both sides 3x + 7 = –6 + 7 = 3x + 7 = 1

(iii) x = –2

Multiplying both sides by 3 3x = –6

Adding 10 to both sides 3x + 10 = –6 + 10 = 3x + 10 = 4

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