NCERT Solutions Class 7 Mathematics Algebraic Expressions Ex 12.4

Class 6 - Mathematics
Chapter - Algebraic Expressions : Exercise 12.4

NCERT Solutions Class 7 Mathematics textbook
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Question : 1.Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators.

(a)   ……..

11 16 21… (5n+1)…

(b) ……..

7 10 13… (3n+1)…

(c)   ……..

7 121722…

If the number of digits formed is taken to be n, the number of segments required to form n digits is given by the algebraic expression appearing on the right of each pattern.

How many segments are required to form 5, 10, 100 digits of the kind

Answer :

SNo.SymbolDigit’s NumberPattern’s FormulaeNo. of Segments
(i)55n + 126
1051
100501
(ii)53n + 116
1031
15301
(iii)55n + 227
1052
15502

(i) 5n+1

Putting n=5, 5 x 5 + 1 = 25 + 1 = 26

Putting n=10, 5 x 10 + 1 = 50 + 1 = 51

Putting n=100, 5 x 100 + 1 = 500 + 1 = 501

(ii) 3n+1

Putting n=5, 3 x 5 + 1 = 15 + 1 = 16

Putting n=10, 3 x 10 + 1 = 30 + 1 = 31

Putting n=100, 3 x 100 + 1 = 300 + 1 = 301

(iii) 5n+2

Putting n=5, 5 x 5 + 2 = 25 + 2 = 27

Putting n=10, 5 x 10 + 2 = 50 + 2 = 52

Putting n=100, 5 x 100 + 2 = 500 + 2 = 502

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Question : 2.Use the given algebraic expression to complete the table of number patterns:

S.No. Expression Terms
1st 2nd 3rd 4th 5th ….. 10th ….. 100th ….
(i) 2n – 1 1 3 5 7 9 19
(ii) 3n + 2 2 5 8 11
(iii) 4n + 1 5 9 13 17
(iv) 7n + 20 27 34 41 48
(v) n2 + 1 2 5 10 17 10001

Answer :
(i) 2n–1

Putting n=100, 2 x 100 – 1 = 200 – 1 = 199

(ii) 3n+2

Putting n=5, 3 x 5 + 2 = 15 + 2 = 17

Putting n=10, 3 x 10 + 2 = 30 + 2 = 32

Putting n=100, 3 x 100 + 2 = 300 + 2 = 302

(iii) 4n+1

Putting n=5, 4 x 5 + 1 = 20 + 1 = 21

Putting n=10, 4 x 10 + 1 = 40 + 1 = 41

Putting n=100, 4 x 100 + 1 = 400 + 1 = 401

(iv) 7n+20

Putting n=5, 7 x 5 + 20 = 25 + 20 = 55

Putting n=10, 7 x 10 + 20 = 70 + 20 = 90

Putting n=100, 7 x 100 + 20 = 700 + 20 = 720

(v) n2+1

Putting n=5, 5 x 5 + 1 = 25 + 1 = 26

Putting n=10, 10 x 10 + 1 = 100 + 1 = 101

Putting n=100, 100 x 100 + 1 = 10000 + 1 = 10001

Now complete table is,

S.No. Expression Terms
1st 2nd 3rd 4th 5th ….. 10th ….. 100th ….
(i) 2n – 1 1 3 5 7 9 19 199
(ii) 3n + 2 2 5 8 11 17 32 302
(iii) 4n + 1 5 9 13 17 21 41 401
(iv) 7n + 20 27 34 41 48 55 90 720
(v) n2 + 1 2 5 10 17 26 101 10001
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