NCERT Solutions Class 7 Mathematics Exponents and Powers Ex 13.1

Class 6 - Mathematics
Chapter - Exponents and Powers : Exercise 13.1

NCERT Solutions Class 7 Mathematics textbook
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Question: 1.Find the value of:

(i) 26

(ii) 93

(iii) 112

(iv) 54

Answer :
(i) 26 = 2 x 2 x 2 x 2 x 2 x 2 = 64

(ii) 93 = 9 x 9 x 9 = 729

(iii) 112 = 11 x 11 = 121

(iv) 54 = 5 x 5 x 5 x 5 = 625

Question: 2.Express the following in exponential form:

(i) 6 x 6 x 6 x 6

(ii) t x t

(iii) b x b x b x b

(iv) 5 x 5 x 7 x 7 x 7

(v) 2 x 2 x a x a

(vi) a x a x a x c x c x c x c x d

Answer :
(i) 6 x 6 x 6 x 6 = 64

(ii) t x t=t2

(iii) b x b x b x b=b4

(iv) 5 x 5 x 7 x 7 x 7 = 52 x 73

(v) 2 x 2 x a x a = 22 x a2

(vi) a x a x a x c x c x c x c x d = a3 x c4 x d

Question: 3.Express each of the following numbers using exponential notation:

(i) 512

(ii) 343

(iii) 729

(iv) 3125

Answer :
(i) 512
= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 29

(ii) 343
= 7 x 7 x 7 = 73

(iii) 729
= 3 x 3 x 3 x 3 x 3 x 3 = 36

(iv) 3125
=5 x 5 x 5 x 5 x 5 = 55

Question: 4.Identify the greater number, wherever possible, in each of the following:

(i) 43 and 34

(ii) 53 or 35

(iii) 28 or 82

(iv) 1002 or 2100

(v) 210 or 102

Answer :
(i) 43 = 4 x 4 x 4 = 64

34 = 3 x 3 x 3 x 3 = 81

Since 64 < 81

Thus, 34 is greater than 43.

(ii) 53 = 5 x 5 x 5 = 125

35 = 3 x 3 x 3 x 3 x 3 = 243

Since, 125 < 243

Thus, 35 is greater than 53.

(iii) 28 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

82 = 8 x 8 = 64

Since, 256 > 64

Thus, 28 is greater than 82.

(iv) 1002 = 100 x 100 = 10,000

2100 = 2 x 2 x 2 x 2 x 2 x …..94 times x ……… x 2 = 16,384 x ….. x 2

Since, 10,000 < 16,384 x ……. X 2

Thus, 2100 is greater than 1002.

(v) 210 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 1,024

102 = 10 x 10 = 100

Since, 1,024 > 100

Thus, 210 > 102

Question: 5.Express each of the following as product of powers of their prime factors:

(i) 648

(ii) 405

(iii) 540

(iv) 3,600

Answer :
(i) 648 = 23 x 34

(ii) 405 = 5 x 34

(iii) 540 = 22 x 33 x 5

(iv) 3,600 = 24 x 32 x 52

Question: 6.Simplify:

(i) 2 x 103

(ii) 72 x 22

(iii) 23 x 5

(iv) 3 x 44

(v) 0 x 102

(vi) 52 x 33

(vii) 24 x 632

(viii) 32 x 104

Answer :
(i) 2 x 103 = 2 x 10 x 10 x 10 = 2,000

(ii) 72 x 22 = 7 x 7 x 2 x 2 = 196

(iii) 23 x 5 = 2 x 2 x 2 x 5 = 40

(iv) 3 x 44 = 3 x 4 x 4 x 4 x 4 = 768

(v) 0 x 102 = 0 x 10 x 10 = 0

(vi) 52 x 33 = 5 x 5 x 3 x 3 x 3 = 675

(vii) 24 x 632 = 2 x 2 x 2 x 2 x 3 x 3 = 144

(viii) 32 x 104 = 3 x 3 x 10 x 10 x 10 x 10 = 90,000

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Question: 7.Simplify:

(i) (–4)3

(ii) (–3) x (–2)3

(iii) (–3)2 x (–5)2

(iv) (–2)3 x (–10)3

Answer :
(i) (–4)3 =(–4) x (–4) x (–4) = –64

(ii) (–3) x (–2)3 =(–3) x (–2) x (–2) x (–2) = 24

(iii) (–3)2 x (–5)2 = (–3) x (–3) x (–5) x (–5) = 225

(iv) (–2)3 x (–10)3 = (–2) x (–2) x (–2) x (–10) x (–10) x (–10)

Question: 8.Compare the following numbers:

(i) 2.7 x 1012; 1.5 x 108

(ii) 4 x 1014; 3 x 1017

Answer :
(i) 2.7 x 1012 and 1.5 x 108

On comparing the exponents of base 10,

2.7 x 1012 > 1.5 x 108

(ii) 4 x 1014 and 3 x 1017

On comparing the exponents of base 10,

4 x 1014 < 3 x 1017

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