NCERT Solutions Class 7 Mathematics Practical Geometry Ex 10.2

Class 6 - Mathematics
Chapter - Practical Geometry : Exercise 10.2

NCERT Solutions Class 7 Mathematics textbook
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Question : 1.Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Answer :
To construct: ΔXYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

NCERT Solutions Class 7 Mathematics Practical Geometry
Steps of construction:

(a) Draw a line segment YZ = 5 cm.

(b) Taking Z as centre and radius 6 cm, draw an arc.

(c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which intersects first arc at point X.

(d) Join XY and XZ.

It is the required ΔXYZ.

Question : 2.Construct an equilateral triangle of side 5.5 cm.

Answer :
To construct: A ΔABC where AB = BC = CA = 5.5 cm

NCERT Solutions Class 7 Mathematics Practical Geometry
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Steps of construction:

(a) Draw a line segment BC = 5.5 cm

(b) Taking points B and C as centre and radius 5.5 cm, draw arcs which intersect at point A.

(c) Join AB and AC.

It is the required ΔABC.

Question : 3.Draw ΔPQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Answer :
To construction: ΔPQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm.

NCERT Solutions Class 7 Mathematics Practical Geometry
Steps of construction:

(a) Draw a line segment QR = 3.5 cm.

(b) Taking Q as centre and radius 4 cm, draw an arc.

(c) Similarly, taking R as centre and radius 4 cm, draw an another arc which intersects first arc at P.

(d) Join PQ and PR.

It is the required isosceles ΔPQR.

Question : 4.Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Answer :
To construct:ΔABC in which AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm.

NCERT Solutions Class 7 Mathematics Practical Geometry
Steps of construction:

(a) Draw a line segment BC = 6 cm.

(b) Taking B as centre and radius 2.5 cm, draw an arc.

(c) Similarly, taking C as centre and radius 6.5 cm, draw another arc which intersects first arc at point A.

(d) Join AB and AC.

(e) Measure angle B with the help of protractor.

It is the required ΔABC where ∠B = 80o.

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