Class 6 - Mathematics
Chapter - Simple Equations : Exercise 4.3
![NCERT Solutions Class 7 Mathematics textbook](https://ncertplanet.com/wp-content/uploads/2020/05/07_Maths_Book.jpg)
Top Block 1
Question: 1.Solve the following equations:
(a) 2y + 5⁄2 = 37⁄2
(b) 5t + 28 = 10
(c) a⁄5 + 3 = 2
(d) q⁄4 + 7 = 5
(e) 5⁄2x = 10
(f) 5⁄2x = 25⁄4
(g) 7m + 19⁄2 = 13
(h) 6z + 10 = –2
(i) 3l⁄2 = 23
(j) 2b⁄3 – 5 = 3
Answer :
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a1_1.jpg)
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a1_2.jpg)
Question: 2.Solve the following equations:
(a) 2 (x + 4) = 12
(b) 3 (n – 5) = 21
(c) 3 (n – 5) = –21
(d) 3 – 2(2 – y) = 7
(e) –4 (2 – x) = 9
(f) 4(2 – x) = 9
(g) 4 +5 (p –1 ) = 34
(h) 34 –5(p – 1) = 4
Answer :
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a2_1.jpg)
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a2_2.jpg)
Mddle block 1
Question: 3.Solve the following equations:
(a) 4 = 5 (p – 2)
(b) –4 = 5 (p – 2)
(c) –16 = –5(2 – p)
(d) 10 = 4 + 3 (t + 2)
(e) 28 = 4 + 3(t + 5)
(f) 0 = 16 + 4(m – 6)
Answer :
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a3_1.jpg)
![NCERT Solutions Class 7 Mathematics Simple Equations](https://ncertplanet.com/wp-content/uploads/2020/05/math7_ex_4_3_a3_2.jpg)
Question: 4.
(a) Construct 3 equations starting with x = 2.
(b) Construct 3 equations starting with x = –2.
Answer :
(a) 3 equations starting with x = 2.
(i) x = 2
Multiplying both sides by 10, 10x = 20
Adding 2 both sides 10x + 2 = 20 + 2 = 10x + 2 = 22
(ii) x = 2
Multiplying both sides by 5 5x = 10
Subtracting 3 from both sides 5x – 3 = 10 –3 = 5x – 3 = 7
(iii) x = 2
Dividing both sides by 5 x⁄5 = 2⁄5
(b) 3 equations starting with x = –2.
(i) x = –2
Multiplying both sides by 3 3x = –6
(ii) x = –2
Multiplying both sides by 3 3x = –6
Adding 7 to both sides 3x + 7 = –6 + 7 = 3x + 7 = 1
(iii) x = –2
Multiplying both sides by 3 3x = –6
Adding 10 to both sides 3x + 10 = –6 + 10 = 3x + 10 = 4