Class 6 - Mathematics : Practical Geometry
Exercise : 14.2
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NCERT Solutions Class 6 Mathematics Practical Geometry Ex 14.2
Question: 1.Draw a line segment of length 7.3 cm, using a ruler.
Answer :
Steps of construction:
(i) Place the zero mark of the ruler at a point A.
(ii) Mark a point B at a distance of 7.3 cm from A.
(iii) Join AB.
AB is the required line segment of length 7.3 cm.
Question: 2.Construct a line segment of length 5.6 cm using ruler and compasses.
Answer :
Steps of construction:
(ii) Place the compasses pointer on zero mark of the ruler. Open it to place the pencil point up to 5.6 cm mark.
(iii) Without changing the opening of the compasses. Place the pointer on A and cut an arc ′l′ at B.
AB is the required line segment of length 5.6 cm.
Question: 3.Construct AB of length 7.8 cm. From this cut off AC of length 4.7 cm. Measure BC.
Answer :
Steps of construction:
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(ii) Mark a point B at a distance 7.8 cm from A.
(iii) Again, mark a point C at a distance 4.7 from A.
By measuring BC, we find that BC = 3.1 cm
Question: 4.Given AB of length 3.9 cm, construct PQ such that the length PQ is twice that of AB. Verify by measurement.
Answer :
Steps of construction:
(ii) Construct PX such that length of PX = length of AB
(iii) Then cut of XQ such that XQ also has the length of AB.
(iv) Thus the length of PX and the length of XQ added together make twice the length of AB.
Verification:
By measurement we find that PQ = 7.8 cm
= 3.9 cm + 3.9 cm = AB + AB = 2 x AB
Question: 5.Given AB of length 7.3 cm and CD of length 3.4 cm, construct a line segment XY such that the length of XY is equal to the difference between the lengths of AB and CD. Verify by measurement.
Answer :
Steps of construction:
(i) Draw a line ′l′ and take a point X on it.
(ii) Construct XZ such that length XZ = length of AB = 7.3 cm
(iii) Then cut off ZY = length of CD = 3.4 cm
(iv) Thus the length of XY = length of AB – length of CD
By measurement we find that length of XY = 3.9 cm
= 73 cm – 3.4 cm = AB − CD