NCERT Solutions Class 7 Mathematics Fractions and Decimals Ex 2.2

Class 6 - Mathematics
Chapter - Fractions and Decimals : Exercise 2.2

NCERT Solutions Class 7 Mathematics textbook
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Question: 1.Which of the drawings (a) to (d) show:

(i)2 × 1⁄5

(ii)2 × 1⁄2

(iii)3 × 2⁄3

(iv)3 × 1⁄4

NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals

Answer :
(i) – (d) Since 2 × 1⁄5 = 1⁄5 + 1⁄5

(ii) – (b) Since 2 × 1⁄2 = 1⁄2 + 1⁄2

(iii) – (a) Since 3 × 2⁄3 = 2⁄3 + 2⁄3 + 2⁄3

(iv) – (c) Since 3 × 1⁄4 = 1⁄4 + 1⁄4 + 1⁄4

Question: 2.Some pictures (a) to (c) are given below. Tell which of them show:

(i)3 × 1⁄5 = 3⁄5

(ii)2 × 1⁄3 = 2⁄5

(iii)3 × 3⁄4 = 21⁄4

NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals
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Answer :
(i) – (c) Since 3 × 1⁄5 = 1⁄5 + 1⁄5 + 1⁄5

(ii) – (a) Since 2 × 1⁄3 = 1⁄3 + 1⁄3

(iii) – (b) Since 3 × 3⁄4 = 3⁄4 + 3⁄4 + 3⁄4

Question: 3.Multiply and reduce to lowest form and convert into a mixed fraction:

(i) 7 × 3⁄5

(ii) 4 × 1⁄3

(iii) 2 × 6⁄7

(iv) 5 × 2⁄9

(v) 2⁄3 × 4

(vi) 5⁄2 × 6

(vii) 11 × 4⁄7

(viii) 20 × 4⁄5

(ix) 13 × 1⁄3

(x) 15 × 3⁄5

Answer :

NCERT Solutions Class 7 Mathematics Fractions and Decimals
NCERT Solutions Class 7 Mathematics Fractions and Decimals

Question: 4.Shade:

(i) 1⁄2 of the circles in box

(ii) 2⁄3 of the triangles in box

(iii) 3⁄5 of the squares inbox

NCERT Solutions Class 7 Mathematics Fractions and Decimals

Answer :
(i) 1⁄2 of 12 circles = 1⁄2 × 12 = 6 circles

NCERT Solutions Class 7 Mathematics Fractions and Decimals
(ii) 2⁄3 of 9 triangles = 2⁄3 × 9 = 2 x 3 = 6 triangles

NCERT Solutions Class 7 Mathematics Fractions and Decimals
(iii) 3⁄5 of 15 squares = 3⁄5 × 15 = 3 x 3 = 9 squares

NCERT Solutions Class 7 Mathematics Fractions and Decimals

Question: 5.Find:

(a) 1⁄2 of (i) 24 (ii) 46

(b) 2⁄3 of (i) 18 (ii) 27

(c) 3⁄4 of (i) 16 (ii) 36

(d) 4⁄5 of (i) 20 (ii) 35

Answer :
(a)

(i) 1⁄2 of 24 = 12

(ii) 1⁄2 of 46 = = 23

(b)

(i) 2⁄3 of 18 = 2⁄3 × 18 = 2 x 6 = 12

(ii) 2⁄3 of 27 = 2⁄3 × 27 = 2 x 9 = 18

(c)

(i) 3⁄4 of 16 = 3⁄4 × 16 = 3 x 4 = 12

(ii) 3⁄4 of 36 = 3⁄4 × 36 = 3 x 9 = 27

(d)

(i) 4⁄5 of 20 = 4⁄5 × 20 = 4 x 4 = 16

(ii) 4⁄5 of 35 = 4⁄5 × 35 = 4 x 7 = 28

Question: 6.Multiply and express as a mixed fraction:

(a) 3 × 51⁄5

(b) 5 × 63⁄4

(c) 7 × 21⁄4

(d) 4 × 61⁄3

(e) 31⁄4 × 6

(f) 32⁄5 × 8

Answer :

NCERT Solutions Class 7 Mathematics Fractions and Decimals

Question: 7.Find:

(a) 1⁄2 of (i) 23⁄4 (ii) 42⁄9

(b) 5⁄8 of (i) 35⁄6 (ii) 92⁄3

Answer :
(a)

NCERT Solutions Class 7 Mathematics Fractions and Decimals
(b)
NCERT Solutions Class 7 Mathematics Fractions and Decimals

Question: 8. Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed 2⁄5 of the water. Pratap consumed the remaining water.

(i)How much water did Vidya drink?

(ii)What fraction of the total quantity of water did Pratap drink?

Answer :
Given: Total quantity of water in bottle = 5 litres

(i) Vidya consumed = 2⁄5 of 5 litres = 2⁄5 × 5 = 2 litres

Thus, Vidya drank 2 litres water from the bottle.

(ii) Pratap consumed = (1–2⁄5) part of bottle

= 5–2⁄5=2⁄5 part of bottle

Pratap consumed 35 of 5 litres water = 2⁄5 × 5 = 3 litres

Thus, Pratap drank 2⁄5 part of the total quantity of water.

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