Class 6 - Mathematics
Chapter - Fractions and Decimals : Exercise 2.3
Top Block 1
Question: 1.Find:
(i) 1⁄4 of
(a) 1⁄4
(b) 3⁄5
(c) 4⁄3
(ii) 1⁄7 of
(a) 2⁄9
(b) 6⁄5
(c) 3⁄10
Answer :
(i)
(a) 1⁄4 of 1⁄4 = 1⁄4 × 1⁄4 = (1×1)⁄(4×4) = 1⁄6
(b) 1⁄4 of 3⁄5 = 1⁄4 × 3⁄5 = (1×3)⁄(4×4) = 3⁄1
(c) 1⁄4 of 4⁄3 = 1⁄4 × 4⁄3 = (1×4)⁄(4×3) = 1⁄43
(ii)
(a) 1⁄7 of 2⁄9 = 1⁄7 × 2⁄9 = (1×2)⁄(7×9) = 2⁄63
(b) 1⁄7 of 6⁄5 = 1⁄7 × 6⁄5 = (1×6)⁄(7×5) = 6⁄35
(c) 1⁄7 of 3⁄10 = 1⁄7 × 3⁄10 = (1×3)⁄(7×10) = 3⁄70
Question: 2.Multiply and reduce to lowest form (if possible):
(i) 2⁄3 × 22⁄3
(ii) 2⁄7 × 7⁄9
(iii) 3⁄8 × 6⁄4
(iv) 9⁄5 × 3⁄5
(v) 1⁄3 × 15⁄8
(vi) 11⁄2 × 3⁄10
(vii) 4⁄5 × 12⁄7
Answer :
Question: 3.Multiply the following fractions:
(i) 2⁄5 × 51⁄4
(ii) 62⁄5 × 7⁄9
(iii) 3⁄2 × 51⁄3
(iv) 5⁄6 × 23⁄7
(v) 32⁄5 × 4⁄7
(vi) 23⁄5 × 3
(vii) 34⁄7 × 3⁄5
Answer :
Mddle block 1
Question: 4.Which is greater:
(i)2⁄7 of 3⁄4 or 3⁄5 of 5⁄8
(ii)1⁄2 of 6⁄7 or 2⁄3 of 3⁄7
Answer :
(i) 2⁄7 of 3⁄4 or 3⁄5 of 5⁄8 ⇒ 2⁄7 of 3⁄4 or 3⁄5 X 5⁄8
⇒ 3⁄14 or 3⁄8 ⇒ 3⁄14<3⁄8
Thus, 3⁄5 of 5⁄8 is greater.
(ii) 1⁄2 of 6⁄7 or 2⁄3 of 3⁄7 ⇒ 1⁄2 of 6⁄7 or 2⁄3 X 3⁄7
⇒ 3⁄7 or 2⁄7 ⇒ 3⁄7 > 2⁄7
Thus, 1⁄2 of 6⁄7 is greater.
Question: 5.Saili plants 4 saplings in a row in her garden. The distance between two adjacent saplings is 3⁄4 m. Find the distance between the first and the last sapling.
Answer :
The distance between two adjacent saplings = 3⁄4 m
Saili planted 4 saplings in a row, then number of gap in saplings
Thus the distance between the first and the last saplings is 21⁄4 m.
Question: 6.Lipika reads a book for 13⁄4 hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read the book?
Answer :
Time taken by Lipika to read a book = 13⁄4 hours.
She reads entire book in 6 days.
Now, total hours taken by her to read the entire book = 13⁄4 × 6 = 7⁄4 × 6 = 21⁄2 = 101⁄2 hours
Thus 10 hours were required by her to read the book.
Question: 7.A car runs 16 km using 1 litre of petrol. How much distance will it cover using 23⁄4 litres of petrol?
Answer :
In 1 litre of pertrol, car covers the distance = 16 km
In 23⁄4 litres of petrol, car covers the distance = 23⁄4 of 16 km = 11⁄4 × 16 = 44 km
Thus, car will cover 44 km distance.
Question: 8.
Answer :
